\[l'_i(x)=(x-x_0)\cdot (x-x_1)\cdots (x-x_{i-1}) \cdot (x-x_{i+1})\cdots (x-x_n)=
Number (0): Everything in this space must add up to 0. The answer is 4-0, placed horizontally; 0-0, placed horizontally; 0-2, placed vertically.
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